-16x^2+170x-300=0

Solution for -16x^2+170x-300=0 equation:

-16x^2+170x-300=0

a = -16; b = 170; c = -300;
Δ = b2-4ac
Δ = 1702-4·(-16)·(-300)
Δ = 9700
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9700}=\sqrt{100*97}=\sqrt{100}*\sqrt{97}=10\sqrt{97}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(170)-10\sqrt{97}}{2*-16}=\frac{-170-10\sqrt{97}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(170)+10\sqrt{97}}{2*-16}=\frac{-170+10\sqrt{97}}{-32}
$